Class 9th Physics Chapter 8 Exercise Solved Numericals

Physics, with its numerous concepts and formulas, often challenges students to understand and apply knowledge effectively. Class 9th Physics Chapter 8 Exercise Solved Numericals delves into.

Chapter 8 of Class 9th Physics, focusing on the thermal properties of matter, is crucial for grasping concepts like temperature, heat, and their applications.

Solved numerical problems not only reinforce theoretical understanding but also prepare students for exams. This article provides detailed explanations.

And solutions to the most critical numerical problems from the chapter, ensuring clarity and confidence for learners.

Topics Covered in These Notes

This section encompasses key areas that are covered in the provided pages. Topics include:

1. The concepts of temperature and heat.
   
2. Properties of thermometric liquids and their role in measurements.
   
3. Conversion formulas between Celsius, Kelvin, and Fahrenheit scales.
   
4. Application-based problems like heat transfer, thermal expansion, and their implications in daily life.

Class 9th Physics Chapter 8 Exercise Solved Numericals

Numerical Problems

1. Conversion Between Temperature Scales
Temperature conversions often appear in exams. Here’s an example:
Convert 50°C to Fahrenheit.

Solution:
Using the formula:
F=(1.8×C)+32F = (1.8 \times C) + 32F=(1.8×C)+32
F=(1.8×50)+32=122∘FF = (1.8 \times 50) + 32 = 122^\circ FF=(1.8×50)+32=122∘F
Result: 50°C equals 122°F.

2. Heat Required to Change Water State
Calculate the heat required to convert 2.5 kg of water at 20°C to boiling at 100°C.
Solution:
Given:

• Mass m=2.5 kgm = 2.5 \, \text{kg}m=2.5kg
• Specific heat of water c=4200 J/kg\cdotpKc = 4200 \, \text{J/kg·K}c=4200J/kg\cdotpK
• Temperature change ΔT=100−20=80∘ C\Delta T = 100 – 20 = 80^\circ \, \text{C}ΔT=100−20=80∘C

Using the formula:
Q=m⋅c⋅ΔTQ = m \cdot c \cdot \Delta TQ=m⋅c⋅ΔT
Q=2.5⋅4200⋅80Q = 2.5 \cdot 4200 \cdot 80Q=2.5⋅4200⋅80
Q=840,000 JQ = 840,000 \, \text{J}Q=840,000J
Result: The heat required is 840 kJ.

3. Determining Kelvin from Celsius
Find the temperature in Kelvin for 20°C.
Solution:
Using the formula:
T(K)=T(C)+273T(K) = T(C) + 273T(K)=T(C)+273
T(K)=20+273=293 KT(K) = 20 + 273 = 293 \, \text{K}T(K)=20+273=293K
Result: The temperature is 293 K.

Tool for Success in Exams

These solved numericals are not just solutions but a guide to approach similar problems effectively. By practicing these, students can develop problem-solving skills and better understand concepts like heat transfer and thermal properties, essential for scoring well.

Colored Notes

In order to enhance learning and retention, the notes provided are presented in a visually engaging format. Important formulas, definitions, and solutions are highlighted in bold or different colors to draw attention to key elements. For instance:

1. Conversion formulas like F=(1.8×C)+32F = (1.8 \times C) + 32F=(1.8×C)+32 are marked prominently.
   
2. Tables summarizing thermometric properties or specific heats of substances are displayed in colored boxes.
   
   These visual cues make the content more appealing and easier to review before exams.

Notes Are Free to Use

One of the significant benefits of these notes is that they are freely accessible to students. This eliminates barriers to quality learning materials, allowing every student to prepare effectively regardless of resources.

The emphasis on providing free, comprehensive, and accurate content underscores the commitment to academic excellence.

Notes Are Mistake-Free

These notes have been meticulously verified to ensure accuracy and reliability. Each numerical solution is cross-checked against established formulas and principles,

Ensuring no errors in calculations. This attention to detail ensures that students can rely on the material without second-guessing its correctness.

Chapter 8 Class 9th Physics Notes

1. Class 9th Physics Chapter 8 Notes (MCQs, Short & Long Questions) 
2. Class 9th Physics Chapter 8 Solved Excercise ( MCQs, Short & Long Questions)

Conclusion

Mastering Chapter 8 of Class 9th Physics, particularly the exercise on solved numericals, is pivotal for building a strong foundation in thermal properties of matter.

With detailed, mistake-free solutions and visually appealing notes, students are equipped to excel in exams. The combination of accurate explanations and practical examples makes these notes an indispensable resource for academic success.

FAQs

Other Chapter Class 9th Physics Notes

1. Class 9th Physics Chapter 6 Solved Exercise ( MCQs, Short & Long Questions)
2. Class 9th Physics Chapter 6 Notes (MCQs, Short & Long Questions)
3. Class 9th Physics Chapter 6 Exercise Solved Numericals
4. Class 9th Physics Chapter 7 Excercise Solved Numericals
5. Class 9th Physics Chapter 7 Solved Excercise ( MCQs, Short & Long Questions)
6. Class 9th Physics Chapter 7 Notes (MCQs, Short & Long Questions)